Question:
Find the angle between the vectors \( \mathbf{a} = (2, -1, 3) \) and \( \mathbf{b} = (1, 4, -2) \).
Find the angle between the vectors \( \mathbf{a} = (2, -1, 3) \) and \( \mathbf{b} = (1, 4, -2) \).
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Use the dot product and magnitudes of vectors to find the angle between them.
Updated On: Jan 13, 2026
- \( 45^\circ \)
- \( 60^\circ \)
- \( 90^\circ \)
- \( 120^\circ \)
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The Correct Option is B
Solution and Explanation
The angle \( \theta \) between two vectors is given by: \[ \cos \theta = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{a}| |\mathbf{b}|}. \] First, calculate the dot product \( \mathbf{a} \cdot \mathbf{b} \): \[ \mathbf{a} \cdot \mathbf{b} = 2 \times 1 + (-1) \times 4 + 3 \times (-2) = 2 - 4 - 6 = -8. \] Next, calculate the magnitudes of \( \mathbf{a} \) and \( \mathbf{b} \): \[ |\mathbf{a}| = \sqrt{2^2 + (-1)^2 + 3^2} = \sqrt{4 + 1 + 9} = \sqrt{14}, \] \[ |\mathbf{b}| = \sqrt{1^2 + 4^2 + (-2)^2} = \sqrt{1 + 16 + 4} = \sqrt{21}. \] Now, calculate \( \cos \theta \): \[ \cos \theta = \frac{-8}{\sqrt{14} \times \sqrt{21}} = \frac{-8}{\sqrt{294}} \approx -0.462. \] Thus, \( \theta \approx 60^\circ \). The correct answer is: \[ \boxed{60^\circ}. \]
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