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\(\mathrm{MnO_2}\) selectively oxidizes allylic and benzylic alcohols to carbonyls.
Updated On: Apr 23, 2026
- (a)
- (b)
- (c)
- (d)
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The Correct Option is B
Solution and Explanation
\[ \mathrm{MnO_2} \xrightarrow{\text{oxidizes}} \text{Allylic } -\mathrm{OH} \rightarrow \mathrm{C=O} \]
\(\mathrm{MnO_2}\) oxidises allylic alcohol
Step 2: Calculation / Simplification}
\(\mathrm{MnO_2}\) is selective for allylic and benzylic alcohols.
In the given diol, only the \(-\mathrm{OH}\) adjacent to the double bond (allylic position) is oxidized.
The isolated \(-\mathrm{OH}\) remains unaffected.
Step 3: Final Answer
\[ \text{Option (b)} \]
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