Fill in the blank:
257, 291, ______, 365, 405
We need to identify the missing number in the sequence: 257, 291, ______, 365, 405.
The best approach is to first determine the pattern or rule governing the sequence. Let's calculate the difference between consecutive terms where possible:
We hypothesize that the differences might increment by a constant value. The difference might form an arithmetic sequence. To test this, we calculate the difference increase from 34 to 40:
Therefore, we suspect the missing difference between 291 and the missing middle number could be 34 + 6 = 40.
Using this logic:
Thus, the missing number that fits the sequence is 327, as the differences would become 34, 36, 38, and 40, showing a steady increment of 2 in the difference values.
Therefore, the correct answer is: 327
Instead of tracking gaps between consecutive terms, notice that each number in this sequence is close to a perfect square. Checking against squares of consecutive integers starting at 16 quickly reveals the pattern: \(16^2 = 256\), and the first term is 257, just 1 more. \(17^2 = 289\), and the second term is 291, 2 more. \(19^2 = 361\), and the fourth term is 365, 4 more. \(20^2 = 400\), and the fifth term is 405, 5 more. So each term equals \((15+k)^2 + k\), where \(k\) is the position of the term in the sequence (1, 2, 3, 4, 5).
For the missing third term, \(k = 3\), so the value should be \(18^2 + 3 = 324 + 3 = 327\).
Since every other term in the sequence equals a perfect square (16 squared through 20 squared) plus its position number, the missing term must equal 18 squared plus 3, which is 327.
Therefore, the correct answer is 327.
Since the sequence looks like it could follow a quadratic rule rather than a simple linear one, we can model each term as \( T_k = Ak^2 + Bk + C \), where \(k\) is the term's position (1 for 257, 2 for the missing term, 4 for 365, and 5 for 405), and solve for the constants \(A\), \(B\), and \(C\) using the terms we already know.
Using position 1: \(A + B + C = 257\). Using position 4: \(16A + 4B + C = 365\). Using position 5: \(25A + 5B + C = 405\). Subtracting the first equation from the equation at position 4 gives \(15A + 3B = 108\), and subtracting the equation at position 4 from the equation at position 5 gives \(9A + B = 40\). Solving these two together, from the second, \(B = 40 - 9A\), substituting into the first, \(15A + 3(40 - 9A) = 108\), which simplifies to \(15A + 120 - 27A = 108\), so \(-12A = -12\), giving \(A = 1\). Then \(B = 40 - 9 = 31\), and from the first original equation, \(C = 257 - 1 - 31 = 225\).
So the rule is \( T_k = k^2 + 31k + 225 \). Checking it against position 2 for the second term (already known to be 291): \(4 + 62 + 225 = 291\), which matches, confirming the formula is correct. The missing term is at position 3: \(T_3 = 9 + 93 + 225 = 327\).
Solving the quadratic model built from the four known terms confirms the missing term is 327.
Therefore, the correct answer is 327.