Question:
Evaluate:
x⁻¹xdx
Evaluate:
x⁻¹xdx
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Choose inverse functions as u in integration by parts.
Updated On: Mar 17, 2026
- \frac12(x²+1)⁻¹x-\frac12x+C
- \frac12(x²+1)⁻¹x+\frac12x+C
- \frac12(x²-1)⁻¹x-\frac12x+C
- None of these
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The Correct Option is A
Solution and Explanation
Using integration by parts:
u=⁻¹x, dv=xdx
x⁻¹xdx=\frac12(x²+1)⁻¹x-\frac12x+C
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