Question:

Evaluate \(\lim_{x \to 0} \frac{x^2 \log(\cos x)}{\log(1+x^2)}\)

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Use Taylor series expansions of \(\cos x\) and \(\log(1+x^2)\) to simplify limit expressions.
Updated On: Jul 18, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Expand numerator and denominator using series.
\(\log(\cos x) \approx \log(1 - x^2/2) \approx -x^2/2\)
\(\log(1 + x^2) \approx x^2\)

Step 2: Substitute expansions.
\(\frac{x^2 \log(\cos x)}{\log(1+x^2)} \approx \frac{x^2 (-x^2/2)}{x^2} = -\frac{x^2}{2}\)

Step 3: Take limit.
\(\lim_{x \to 0} -x^2/2 = 0\)

Step 4: Final conclusion.
Hence, \[ \boxed{0} \]
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