Concept:
For integrals of the form
\[
\int \frac{1}{(x^4+1)^{5/4}}\,dx,
\]
it is convenient to verify the given options by differentiation.
Step 1: Differentiate Option (C).
Let
\[
F(x)=\frac{x}{(x^4+1)^{1/4}}
=
x(x^4+1)^{-1/4}.
\]
Using the product rule,
\[
F'(x)
=
(x^4+1)^{-1/4}
+
x\left(-\frac14\right)(x^4+1)^{-5/4}(4x^3).
\]
\[
=
(x^4+1)^{-1/4}
-
x^4(x^4+1)^{-5/4}.
\]
Taking
\[
(x^4+1)^{-5/4}
\]
common,
\[
F'(x)
=
(x^4+1)^{-5/4}
\Big[(x^4+1)-x^4\Big].
\]
\[
=
(x^4+1)^{-5/4}.
\]
\[
=
\frac{1}{(x^4+1)^{5/4}}.
\]
Step 2: Compare with the integrand.
Since
\[
F'(x)
=
\frac{1}{(x^4+1)^{5/4}},
\]
we have
\[
\int \frac{1}{(x^4+1)^{5/4}}\,dx
=
\frac{x}{(x^4+1)^{1/4}}
+C.
\]
Therefore,
\[
\boxed{\int \frac{1}{(x^4+1)^{5/4}}\,dx
=
\frac{x}{(x^4+1)^{1/4}}+C}
\]
\[
\boxed{\text{Answer = (C)}}
\]