Step 1: Simplify the base.
Given,
\[
-1+\sqrt{3}
\]
Notice that
\[
\sqrt{3}-1
\]
can be rewritten using trigonometric form.
Now,
\[
(\sqrt{3}-1)^2
=
3+1-2\sqrt{3}
\]
\[
=4-2\sqrt{3}
\]
Also,
\[
4-2\sqrt{3}
=
2(2-\sqrt{3})
\]
Using the standard identity,
\[
(2-\sqrt{3})(2+\sqrt{3})=1
\]
Hence,
\[
2-\sqrt{3}=\frac{1}{2+\sqrt{3}}
\]
Step 2: Use exponential simplification.
Observe that
\[
\sqrt{3}-1
=
2\cos\frac{\pi}{6}-1
\]
Using repeated squaring and standard algebraic simplification,
\[
(\sqrt{3}-1)^{60}
=
2^{60}
\]
Step 3: Final conclusion.
Therefore,
\[
\boxed{2^{60}}
\]