Question:
Equation of line through \( (a,b) \) parallel to \( \frac{x}{a} + \frac{y}{b} = 1 \)
Equation of line through \( (a,b) \) parallel to \( \frac{x}{a} + \frac{y}{b} = 1 \)
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Parallel lines → same coefficients, different constant.
Updated On: May 1, 2026
- \( \frac{x}{a} + \frac{y}{b} = 3 \)
- \( \frac{x}{a} + \frac{y}{b} = 2 \)
- \( \frac{x}{a} + \frac{y}{b} = 0 \)
- \( \frac{x}{a} + \frac{y}{b} +2=0 \)
- \( \frac{x}{a} + \frac{y}{b} = 4 \)
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The Correct Option is B
Solution and Explanation
Concept: Parallel lines differ only in constant.
Step 1: General form: \[ \frac{x}{a} + \frac{y}{b} = k \]
Step 2: Substitute point \( (a,b) \).
\[ 1+1= k \]
Step 3: So: \[ k=2 \]
Step 4: Equation: \[ \frac{x}{a} + \frac{y}{b} = 2 \]
Step 5: Final answer confirmed.
Step 1: General form: \[ \frac{x}{a} + \frac{y}{b} = k \]
Step 2: Substitute point \( (a,b) \).
\[ 1+1= k \]
Step 3: So: \[ k=2 \]
Step 4: Equation: \[ \frac{x}{a} + \frac{y}{b} = 2 \]
Step 5: Final answer confirmed.
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