Question:

Equation of circle with centre \( (2,2) \) passing through \( (4,5) \)

Show Hint

Use distance formula to find radius.
Updated On: May 1, 2026
  • \( x^2+y^2-4x+4y-77=0 \)
  • \( x^2+y^2-4x-4y-5=0 \)
  • \( x^2+y^2+2x+2y-59=0 \)
  • \( x^2+y^2-2x-2y-23=0 \)
  • \( x^2+y^2+4x-2y-26=0 \)
Show Solution
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The Correct Option is D

Solution and Explanation

Concept: Circle equation: \[ (x-h)^2+(y-k)^2=r^2 \]

Step 1:
Centre \( (2,2) \).

Step 2:
Find radius.
\[ r^2=(4-2)^2+(5-2)^2=4+9=13 \]

Step 3:
Write equation.
\[ (x-2)^2+(y-2)^2=13 \]

Step 4:
Expand.
\[ x^2-4x+4 + y^2-4y+4=13 \]

Step 5:
Simplify.
\[ x^2+y^2-4x-4y-5=0 \]
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