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equation of circle with centre 2 2 passing through
Question:
Equation of circle with centre \( (2,2) \) passing through \( (4,5) \)
Show Hint
Use distance formula to find radius.
KEAM - 2018
KEAM
Updated On:
May 1, 2026
\( x^2+y^2-4x+4y-77=0 \)
\( x^2+y^2-4x-4y-5=0 \)
\( x^2+y^2+2x+2y-59=0 \)
\( x^2+y^2-2x-2y-23=0 \)
\( x^2+y^2+4x-2y-26=0 \)
Show Solution
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The Correct Option is
D
Solution and Explanation
Concept:
Circle equation: \[ (x-h)^2+(y-k)^2=r^2 \]
Step 1:
Centre \( (2,2) \).
Step 2:
Find radius.
\[ r^2=(4-2)^2+(5-2)^2=4+9=13 \]
Step 3:
Write equation.
\[ (x-2)^2+(y-2)^2=13 \]
Step 4:
Expand.
\[ x^2-4x+4 + y^2-4y+4=13 \]
Step 5:
Simplify.
\[ x^2+y^2-4x-4y-5=0 \]
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