Step 1: Set up the line.
A, B, C, D lie on a straight line in that order, so the whole segment AD splits into three parts: AB, BC, and CD.
Also \( AC = AB + BC \), since AC is made up of AB and BC together.
We need to check if AB = BC = CD.
Step 2: Test statement I alone.
Statement I says \( AC = 2\,CD \), that is, \( AB + BC = 2\,CD \).
This is one equation with three unknowns (AB, BC, CD), so many different combinations of AB, BC, CD can satisfy it without AB, BC, CD being equal.
For example, AB = 1, BC = 3, CD = 2 gives AC = 4 = 2(2), which fits, but AB, BC, CD are not all equal here.
So statement I alone is not enough.
Step 3: Test statement II alone.
Statement II says \( AB = BC \), but it says nothing about CD.
CD could be any length, so we cannot conclude AB = BC = CD from this alone.
So statement II alone is not enough either.
Step 4: Combine statement I and statement II.
From statement II, \( AB = BC \), so \( AC = AB + BC = 2\,AB \).
From statement I, \( AC = 2\,CD \).
Equating the two expressions for AC: \( 2\,AB = 2\,CD \), so \( AB = CD \).
Since we already have \( AB = BC \) and now \( AB = CD \), it follows that \( AB = BC = CD \).
Final Answer:
Both statements are needed together to confirm AB = BC = CD; neither alone is enough.
\[ \boxed{\text{Option (3)}} \]