To determine the lightest ball among the five, let's analyze the conditions given in the question:
- Black ball is heavier than the Red and Blue balls.
- Yellow ball is lighter than the Red ball.
- Blue ball is heavier than the Red and Green balls.
We need to establish the relative weight order of the balls based on these conditions:
- From condition (i), we know: \(B_{black} > B_{red}\) and \(B_{black} > B_{blue}\).
- From condition (ii), we know: \(B_{red} > B_{yellow}\).
- From condition (iii), we know: \(B_{blue} > B_{red}\) and \(B_{blue} > B_{green}\).
Now, by putting these together, let's derive possible weight rankings:
- If we consider the Blue ball: \(B_{black} > B_{blue} > B_{red}\), and hence, \(B_{blue} > B_{green}\) and \(B_{blue} > B_{red} > B_{yellow}\).
Therefore, since the Yellow and Green balls are not directly compared, either could be the lightest. The sequence can thus be:
- If \(B_{yellow} < B_{green}\), then \(B_{yellow}\) is the lightest.
- If \(B_{green} < B_{yellow}\), then \(B_{green}\) is the lightest.
Thus, the correct answer is Either Yellow or Green, as both conditions are possible based on the given information.