Question

(e) Find the slope of the curve \( y = 2x^2 - 3\cos x \) at \( x = 0 \).

Hint:

For slope, differentiate the function and substitute the given point.

Answer 1

Differentiatethegivencurve: \[ \frac{dy}{dx}=\frac{d}{dx}(2x^2-3\cosx)=4x+3\sinx. \] At\(x=0\): \[ \frac{dy}{dx}=4(0)+3\sin(0)=0. \]