Differentiating\(ay^2=x^3\)withrespectto\(x\):
\[
2ay\frac{dy}{dx}=3x^2.
\]
At\((am^2,am^3)\),substitute\(x=am^2\)and\(y=am^3\):
\[
2a(am^3)\frac{dy}{dx}=3(am^2)^2.
\]
\[
2am^3\frac{dy}{dx}=3a^2m^4.
\]
\[
\frac{dy}{dx}=\frac{3am^4}{2m^3}=\frac{3am}{2}.
\]