Question

During thermodynamic process, the increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?

• A. Isothermal
• B. Adiabatic
• C. Isochoric
• D. Isobaric

Hint:

In an adiabatic compression, work done on the gas increases its temperature and internal energy.

Answer 1

The Correct Option is B

Step 1: First Law of Thermodynamics
$\Delta Q = \Delta U + \Delta W$, where $\Delta Q$ is heat added, $\Delta U$ is change in internal energy, and $\Delta W$ is work done by the system.
Step 2: Analysis of Given Condition
Work done \textit{on} the system means $\Delta W$ is negative. The problem states $\Delta U = -\Delta W$. Substituting this into the first law:
$\Delta Q = (-\Delta W) + \Delta W = 0$.
Step 3: Process Identification
A process where there is no heat exchange ($\Delta Q = 0$) is an adiabatic process.
Step 4: Conclusion
The process is adiabatic.
Final Answer:(B)