First find how many students were shortlisted for exactly two companies (not all three), by removing the triple-overlap from each pairwise overlap.
Exactly A and B only: \(14-8=6\)
Exactly A and C only: \(12-8=4\)
Exactly B and C only: \(15-8=7\)
Now subtract these exactly-two counts and the all-three count (8) from each company total to get the only-this-company counts:
Only B \(=26-6-7-8=5\)
Only C \(=29-4-7-8=10\)
So the ratio of students shortlisted only for B to only for C is \(5:10=1:2\).
Hence, the correct answer is Option B: 1:2.