To solve the given question regarding the melting of a slab of ice at 273 K and atmospheric pressure, let's analyze the situation step by step.
When ice melts at 273 K and under atmospheric pressure, the following points are important:
Let's evaluate the given options:
Thus, the correct answer is that positive work is done on the ice-water system by the atmosphere, which aligns with Option 4.
Volume decreases during melting of ice so positive work is done on ice water system by atmosphere.
Heat absorbed by ice water so \( \Delta Q \) is positive, work done by ice water system is negative.
Hence by first law of thermodynamics \( \Delta U = \Delta Q + \Delta W = \) Positive So internal energy increases.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)