Question:
Dipole-dipole interaction energy between polar molecules in solids depends on radius r and is directly proportional to
Dipole-dipole interaction energy between polar molecules in solids depends on radius r and is directly proportional to
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Dipole-dipole ∝ 1/r$^3$, dispersion ∝ 1/r$^6$.
Updated On: May 2, 2026
- $\frac{1}{r^2}$
- $\frac{1}{r^6}$
- $\frac{1}{r}$
- $\frac{1}{r^3}$
- $\frac{1}{r^3}$
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The Correct Option is D
Solution and Explanation
Concept: Dipole-dipole interaction
---
Step 1: Formula
\[ E \propto \frac{1}{r^3} \] ---
Step 2: Physical meaning
• Dipole interaction decreases with distance
• Falls faster than Coulomb interaction ---
Step 3: Compare interactions
• Coulomb → $\frac{1}{r}$
• Dipole → $\frac{1}{r^3}$
• London forces → $\frac{1}{r^6}$ --- Final Answer: \[ \boxed{\frac{1}{r^3}} \]
---
Step 1: Formula
\[ E \propto \frac{1}{r^3} \] ---
Step 2: Physical meaning
• Dipole interaction decreases with distance
• Falls faster than Coulomb interaction ---
Step 3: Compare interactions
• Coulomb → $\frac{1}{r}$
• Dipole → $\frac{1}{r^3}$
• London forces → $\frac{1}{r^6}$ --- Final Answer: \[ \boxed{\frac{1}{r^3}} \]
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