Concept:
A diode is:
• Forward biased if anode is at higher potential than cathode
• Reverse biased if anode is at lower potential than cathode
(The triangle side is anode, vertical line is cathode)
Step 1: Analyze Fig (1)
Left side = $0\,V$, right side = $-4\,V$
\[
\text{Anode at } 0V,\quad \text{Cathode towards } -4V
\]
Since:
\[
0V > -4V
\]
\[
\Rightarrow D_1 \text{ is forward biased}
\]
Step 2: Analyze Fig (2)
Left side = $-5\,V$, right side = $-3\,V$
\[
\text{Anode at } -5V,\quad \text{Cathode towards } -3V
\]
Since:
\[
-5V < -3V
\]
\[
\Rightarrow D_2 \text{ is reverse biased}
\]
Conclusion:
$D_1$ is forward biased and $D_2$ is reverse biased.
Final Answer: Option (C)