Question:

Derivative of Average cost \((AC)=5+\frac{2}{Q}\) is:

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Convert fractions into powers before differentiating: \(\frac{1}{Q}=Q^{-1}\). Then use \(\frac{d}{dQ}(Q^n)=nQ^{n-1}\).
Updated On: May 22, 2026
  • \(-\frac{2}{Q^2}\)
  • \(\frac{2}{Q^2}\)
  • \(\frac{2}{Q}\)
  • \(\frac{1}{Q}\)
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The Correct Option is A

Solution and Explanation

Concept: Derivative measures the rate of change of a function. Here, we have to differentiate the average cost function with respect to \(Q\). \[ AC=5+\frac{2}{Q} \]

Step 1:
Rewrite the function using power form.
\[ AC=5+2Q^{-1} \]

Step 2:
Differentiate each term with respect to \(Q\).
\[ \frac{d}{dQ}(5)=0 \] and \[ \frac{d}{dQ}(2Q^{-1})=2(-1)Q^{-2} \]

Step 3:
Simplify the derivative.
\[ \frac{d(AC)}{dQ}=-2Q^{-2} \] \[ \frac{d(AC)}{dQ}=-\frac{2}{Q^2} \] Therefore, the correct answer is option (A).
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