Decarboxylation of sodium propionate leads to the formation of
Show Hint
- methane
- ethene
- propanoic acid
- ethane
The Correct Option is D
Solution and Explanation
Decarboxylation is the removal of CO\(_2\) from a carboxylic acid or its salt. Sodium salts of carboxylic acids on decarboxylation with soda lime (NaOH + CaO) yield alkanes.
Step 2: Detailed Explanation:
Sodium propionate is \(CH_3CH_2COONa\). Upon heating with soda lime, it undergoes decarboxylation: \[ CH_3CH_2COONa + NaOH \xrightarrow{CaO, \Delta} CH_3CH_3 + Na_2CO_3 \] The product is ethane.
Step 3: Final Answer:
Decarboxylation of sodium propionate gives ethane, option (D).
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