Question:

Cyclohexene on oxidation with \( \text{KMnO}_4 \) in dil. \( \text{H}_2\text{SO}_4 \) forms

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Oxidative cleavage of Cyclohexene $\rightarrow$ Adipic Acid (6 carbons).
Updated On: May 14, 2026
  • Cyclohexanol
  • Cyclohexanone
  • Hexanoic acid
  • Adipic acid
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The Correct Option is D

Solution and Explanation


Step 1: Concept

Strong oxidizing agents like acidified $\text{KMnO}_4$ cause oxidative cleavage of double bonds.

Step 2: Meaning

Cleavage of a cyclic alkene results in an open-chain dicarboxylic acid.

Step 3: Analysis

Cyclohexene has a 6-carbon ring with one double bond. Acidified $\text{KMnO}_4$ breaks the $\text{C=C}$ bond and oxidizes the terminal carbons to carboxyl groups ($\text{-COOH}$).

Step 4: Conclusion

This results in hexane-1,6-dioic acid, commonly known as Adipic acid. Final Answer: (D)
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