Step 1: Understanding the Question:
The question asks for the Curie temperature ($T_c$) of ferrite ($\alpha$-iron), which is the critical transition temperature at which the material changes from ferromagnetic to paramagnetic.
Step 2: Detailed Explanation:
• What is Curie Temperature?
The Curie temperature is the temperature above which a ferromagnetic material loses its permanent magnetic properties and becomes paramagnetic.
At this temperature, the thermal energy ($k_B T$) is sufficient to overcome the magnetic exchange coupling that aligns the individual atomic magnetic dipoles.
• Curie Temperature of Ferrite:
Alpha-ferrite ($\alpha$-Fe) is strongly ferromagnetic at room temperature.
As temperature increases, the magnetic alignment begins to randomize.
At exactly $768 \ ^\circ\text{C}$ (approximately 1043 K), ferrite undergoes a magnetic phase transition and becomes paramagnetic.
This is known as the Curie point of iron. Note that there is no change in crystal structure at $768 \ ^\circ\text{C}$; it remains BCC.
• Other Temperatures on the Iron-Carbon Diagram:
- $727 \ ^\circ\text{C}$ is the eutectoid temperature ($A_1$ line).
- $910 \ ^\circ\text{C}$ is the allotropic transformation temperature from BCC ($\alpha$-ferrite) to FCC ($\gamma$-austenite) ($A_3$ line).
- $1147 \ ^\circ\text{C}$ is the eutectic transformation temperature of cast iron.
Step 3: Final Answer:
The Curie temperature of ferrite is 768 $^\circ$C.