Concept:
Electromagnetic waves are arranged in the electromagnetic spectrum according to:
• Frequency
• Wavelength
• Energy
Important relation:
\[
c=f\lambda
\]
where:
• \(c\) = speed of light
• \(f\) = frequency
• \(\lambda\) = wavelength
As frequency increases:
• Wavelength decreases
• Energy increases
The standard order of electromagnetic waves from lowest frequency to highest frequency is:
\[
\text{Radio waves} \rightarrow \text{Microwaves} \rightarrow \text{Infrared} \rightarrow \text{Visible light} \rightarrow \text{Ultraviolet} \rightarrow \text{X-rays} \rightarrow \text{Gamma rays}
\]
Step 1: Identify the lowest frequency radiation.
Among the given radiations:
• Radio waves have the lowest frequency.
Thus:
\[
\text{First} = B
\]
Step 2: Determine the next higher frequency region.
Microwaves possess frequency greater than radio waves but smaller than visible light.
Therefore:
\[
\text{Second} = A
\]
Step 3: Place visible light.
Visible light has frequency higher than microwaves and lower than X-rays.
Thus:
\[
\text{Third} = C
\]
Step 4: Place X-rays and gamma rays.
Among all listed radiations:
• X-rays have very high frequency.
• Gamma rays have the highest frequency.
Therefore:
\[
D \rightarrow E
\]
Step 5: Write complete increasing order.
Hence the correct sequence is:
\[
B, A, C, D, E
\]
That is:
\[
\text{Radio wave} \rightarrow \text{Microwave} \rightarrow \text{Visible light} \rightarrow \text{X-ray} \rightarrow \text{Gamma rays}
\]
Step 6: Write the final answer.
Therefore, the correct option is:
\[
\boxed{(B)\ B, A, C, D, E}
\]