Question:

Copper crystallises in a face-centred cubic lattice with a unit cell length of \(361\) pm. What is the radius of copper atom in pm?

Show Hint

In an fcc lattice the atoms touch along the face diagonal, so r = a / (2 sqrt 2).
Updated On: Nov 12, 2026
  • \(157.6\)
  • \(181.5\)
  • \(108.4\)
  • \(127.6\)
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
In fcc the atoms touch along the face diagonal, which has length \(\sqrt{2}\,a=4r\).

Step 2: Formula
\(r=\dfrac{a}{2\sqrt{2}}\)

Step 3: Calculation
\(r=\dfrac{361}{2\times 1.414}=\dfrac{361}{2.828}=127.6\) pm

Step 4: Compare the options
This matches option (D).

Final Answer:
The radius of a copper atom is 127.6 pm. \[ \boxed{\text{(D) }127.6} \]
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