Step 1: Understanding the Concept
In fcc the atoms touch along the face diagonal, which has length \(\sqrt{2}\,a=4r\).
Step 2: Formula
\(r=\dfrac{a}{2\sqrt{2}}\)
Step 3: Calculation
\(r=\dfrac{361}{2\times 1.414}=\dfrac{361}{2.828}=127.6\) pm
Step 4: Compare the options
This matches option (D).
Final Answer:
The radius of a copper atom is 127.6 pm.
\[ \boxed{\text{(D) }127.6} \]