Question:

Consider the reaction: Cl₂(aq) + H₂S(aq) → S(s) + 2H⁺(aq) + 2Cl⁻(aq) The rate equation for this reaction is: rate = k[Cl₂][H₂S] Which of these mechanisms is/are consistent with the rate equation? A. Cl₂ + H₂S → H⁺ + Cl⁻ + Cl⁺ + HS⁻ (slow) Cl⁺ + HS⁻ → H⁺ + Cl⁻ + S (fast) B. H₂S rightleftharpoons H⁺ + HS⁻ (fast equilibrium) Cl₂ + HS⁻ → 2Cl⁻ + H⁺ + S (slow)

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The rate law must be derivable directly from the slow step of the mechanism without involving intermediates.
Updated On: Mar 19, 2026
  • B only
  • Both A and B
  • Neither A nor B
  • A only
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The Correct Option is D

Solution and Explanation

Mechanism A: The slow (rate-determining) step is: Cl₂ + H₂S → ⋯ Hence, rate = k[Cl₂][H₂S] This matches the given rate law. Mechanism B: From the fast equilibrium: [HS⁻] = K[H₂S] Rate-determining step: rate = k[Cl₂][HS⁻] = k'[Cl₂][H₂S] However, since HS⁻ is an intermediate explicitly appearing, the mechanism does not directly justify the observed rate law without assumptions. Thus, only mechanism A is consistent.
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