Step 1: Identify Molecule \(Y\) - In the reaction \(\text{X} + \text{O}_2 \rightarrow \text{Cu}_2\text{O} + \text{SO}_2\), the gas produced is \(\text{SO}_2\). - Therefore, \(Y\) is \(\text{SO}_2\).
Step 2: Structure of \(\text{SO}_2\) - \(\text{SO}_2\) has a bent (or V-shaped) structure due to the presence of a lone pair on the sulfur atom and two S–O double bonds. - The bond angle is approximately \(119^\circ\), which makes it an \emph{angular} molecule. Hence, the shape of molecule \(Y\) (\(\text{SO}_2\)) is (angular).
| Molisch's lest | Barfoed Test | Biuret Test | |
|---|---|---|---|
| A | Positive | Negative | Negativde |
| B | Positive | Positive | Negative |
| C | Negative | Negative | Positive |
According to MO theory, the molecule which contain only π-Bonds between the atoms is
In which if the following changes there is no change in hybridization of the central atom?
For the reaction at 25° C, X2O4 (l) → 2XO2(g), U and S are 2.1 K.Cal and 20 Cal/K respectively. what is G for the reaction at the same temperature? (R = 2 CAL K-1MOL-1)
The hybrids of which group elements of the periodic table form electron precise hybrids?