Question

Consider the following reaction sequence:

Isomers are:

• A. \( \text{C} \) and \( \text{E} \)
• B. \( \text{C} \) and \( \text{D} \)
• C. \( \text{D} \) and \( \text{E} \)
• D. \( \text{C} \) and \( \text{D} \)

Hint:

Alcoholic KOH is often used for elimination reactions, such as the formation of alkenes from alkyl halides.

Answer 1

The Correct Option is C

Step 1: Analyzing the reaction sequence.
In the given reaction, acetic acid undergoes a reaction with \( \text{PBr}_3 \) to form an intermediate, followed by a reaction with alcoholic KOH to form isomers. The correct isomers are \( \text{D} \) and \( \text{E} \).

Step 2: Conclusion.
The isomers formed in the reaction are \( \text{D} \) and \( \text{E} \), corresponding to option (3).