Question:
Consider a transistor amplifier in common emitter configuration. If the current amplification factor, collector resistance and base resistance are increased by 1%, 2% and 1% respectively, then the change in voltage gain is:
Consider a transistor amplifier in common emitter configuration. If the current amplification factor, collector resistance and base resistance are increased by 1%, 2% and 1% respectively, then the change in voltage gain is:
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In percentage change problems, treat multiplication as addition and division as subtraction.
Updated On: Jun 20, 2026
- 1%
- 2%
- 3%
- 4%
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The Correct Option is B
Solution and Explanation
Step 1: Voltage gain relation in CE amplifier.
Voltage gain is approximately: \[ A_v \propto \beta \cdot \frac{R_C}{R_B} \] So, \[ A_v \propto \beta, \; R_C, \; \frac{1}{R_B} \]
Step 2: Percentage change rule.
For multiplication/division: \[ \frac{\Delta A_v}{A_v} = \frac{\Delta \beta}{\beta} + \frac{\Delta R_C}{R_C} - \frac{\Delta R_B}{R_B} \]
Step 3: Substitute values.
\[ = 1\% + 2\% - 1\% \]
Step 4: Compute net change.
\[ = 2\% \]
Step 5: Final interpretation.
Increase in collector resistance increases gain, while increase in base resistance decreases it. Net effect is 2%.
\[ \boxed{2\%} \]
Voltage gain is approximately: \[ A_v \propto \beta \cdot \frac{R_C}{R_B} \] So, \[ A_v \propto \beta, \; R_C, \; \frac{1}{R_B} \]
Step 2: Percentage change rule.
For multiplication/division: \[ \frac{\Delta A_v}{A_v} = \frac{\Delta \beta}{\beta} + \frac{\Delta R_C}{R_C} - \frac{\Delta R_B}{R_B} \]
Step 3: Substitute values.
\[ = 1\% + 2\% - 1\% \]
Step 4: Compute net change.
\[ = 2\% \]
Step 5: Final interpretation.
Increase in collector resistance increases gain, while increase in base resistance decreases it. Net effect is 2%.
\[ \boxed{2\%} \]
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