Step 1: Setup:
Each face has probability \(\tfrac16\). If the face is 6 the player wins Rs. 36. For \(k=1,2,3,4,5\), he loses Rs. \(k^2\), so his winning is \(-k^2\).
Step 2: Expected Value:
\[ E=\frac16\left[36-(1+4+9+16+25)\right]=\frac16(36-55) \]
Step 3: Compute:
\[ E=\frac{-19}6 \]
Step 4: Check the Options:
A positive value like \(\tfrac{19}6\) comes from reversing the sign of the loss. \(\tfrac32\) and \(-\tfrac32\) do not come from this sum (they would need totals of \(+9\) and \(-9\)). Only \(-\tfrac{19}6\) fits, option (B).
Final Answer:
The expected winning is \(-\dfrac{19}6\) rupees, option (B).
\[ \boxed{\text{(B) } -\frac{19}{6}} \]