Question

Conductivity cell is filled with 0.01 M KCl gives a resistance of 484\(\Omega\) and conductivity of 0.004141 \(\Omega\)\(^{-1}\) cm\(^{-1}\) at 25°C. What is the cell constant?

• A. 0.682 cm\(^{-1}\)
• B. 0.341 cm\(^{-1}\)
• C. 0.751 cm\(^{-1}\)
• D. 0.510 cm\(^{-1}\)

Hint:

The cell constant depends on the geometry of the conductivity cell, and the product of conductivity and resistance gives the cell constant.

Answer 1

The Correct Option is A

Step 1: Understanding the relationship.
The cell constant \( K \) is given by the formula: \[ K = \frac{\text{Conductivity} \times \text{Resistance}}{\text{Length of cell}} \] where Conductivity = 0.004141 \(\Omega^{-1}\) cm\(^{-1}\) and Resistance = 484\(\Omega\). We use this formula to calculate the cell constant.

Step 2: Applying the values.
Substituting the given values, we calculate the cell constant: \[ K = \frac{0.004141 \times 484}{1} = 0.682 \, \text{cm}^{-1} \]
Step 3: Conclusion.
The correct answer is (A) 0.682 cm\(^{-1}\), which is the calculated cell constant.