Question

Compound A and B are treated with dil. HCl separately. The gases liberated are Y and Z respectively. Y turns acidified dichromate paper green while Z turns lead acetate paper black. The compound A and B are respectively:

• A. Na\(_2\)CO\(_3\) and NaCl
• B. Na\(_2\)SO\(_3\) and Na\(_2\)S
• C. Na\(_2\)SO\(_3\) and Na\(_2\)SO\(_3 \)
• D. Na\(_2\)SO\(_3\) and Na\(_2\)SO\(_3\)

Hint:

Sulfites react with acidic solutions to release sulfur dioxide gas (Y), while sulfides form black precipitates with lead acetate (Z).

Answer 1

The Correct Option is B

Step 1: Understand the reactions.
Y turns the dichromate paper green due to the formation of a sulfate, while Z causes the lead acetate paper to turn black due to the formation of sulfides.
Step 2: Conclusion.
Thus, the compounds are sodium sulfite and sodium sulfide.
Final Answer: \[ \boxed{B} \]