Question:

Choose the Swarts reaction in the following:

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Halogen exchange memory trick:
- Finkelstein is for Iodine (FI).
- Swarts is for Fluorine (SF).
Updated On: Apr 29, 2026
  • \(CH_3OH + PCl_5 \to CH_3Cl + POCl_3 + HCl\)
  • \(2CH_3Cl + 2Na \to C_2H_6 + 2NaCl\)
  • \(CH_3Br + AgF \to CH_3F + AgBr\)
  • \(CH_3Cl + NaI \to CH_3I + NaCl\)
  • \(CH_3I + CH_3ONa \to CH_3-O-CH_3 + NaI\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The Swarts reaction is the best method for preparing alkyl fluorides by halogen exchange.

Step 3: Detailed Explanation:

In this reaction, alkyl bromides or alkyl chlorides are heated with metallic fluorides such as silver fluoride (\(AgF\)), mercury fluoride (\(Hg_2F_2\)), or antimony fluoride (\(SbF_3\)).
- Option (B) is the Wurtz reaction.
- Option (C) is the Swarts reaction, as it involves the exchange of \(Br\) for \(F\) using \(AgF\).
- Option (D) is the Finkelstein reaction.
- Option (E) is the Williamson ether synthesis.

Step 4: Final Answer:

The Swarts reaction is \(CH_3Br + AgF \to CH_3F + AgBr\).
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