Question:
Choose the correct expression for ion velocity in mass spectrometry:
Choose the correct expression for ion velocity in mass spectrometry:
Show Hint
Remember the basic kinetic energy formula $1/2 mv^2$ and just solve for $v$!
Updated On: May 28, 2026
- $v=((2.K.E)/\mathfrak{m})^{1.5}$
- $v=((2.K.E)/m)^{0.5}$
- $v=((2.K.E)/\mathfrak{m})^{2}$
- $v=((K.E)/2.m)^{0.5}$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
In mass spectrometry, ions are accelerated by an electric field, converting potential energy into kinetic energy ($K.E$).
Step 2: Meaning
Kinetic energy is defined by the classical physics formula $K.E = \frac{1}{2}mv^2$, where $m$ is the mass of the ion and $v$ is its velocity.
Step 3: Analysis
To find the velocity, we rearrange the kinetic energy equation: $$2 \cdot K.E = m \cdot v^2$$ $$v^2 = \frac{2 \cdot K.E}{m}$$ $$v = \sqrt{\frac{2 \cdot K.E}{m}} = \left(\frac{2 \cdot K.E}{m}\right)^{0.5}$$
Step 4: Conclusion
The expression $\left(\frac{2 \cdot K.E}{m}\right)^{0.5}$ correctly describes the ion velocity.
Final Answer: (B)
In mass spectrometry, ions are accelerated by an electric field, converting potential energy into kinetic energy ($K.E$).
Step 2: Meaning
Kinetic energy is defined by the classical physics formula $K.E = \frac{1}{2}mv^2$, where $m$ is the mass of the ion and $v$ is its velocity.
Step 3: Analysis
To find the velocity, we rearrange the kinetic energy equation: $$2 \cdot K.E = m \cdot v^2$$ $$v^2 = \frac{2 \cdot K.E}{m}$$ $$v = \sqrt{\frac{2 \cdot K.E}{m}} = \left(\frac{2 \cdot K.E}{m}\right)^{0.5}$$
Step 4: Conclusion
The expression $\left(\frac{2 \cdot K.E}{m}\right)^{0.5}$ correctly describes the ion velocity.
Final Answer: (B)
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