Step 1: Understanding the Concept
Acetyl chloride with anhydrous \(\text{AlCl}_3\) gives the acylium ion \(\text{CH}_3\text{CO}^+\), so this is a Friedel-Crafts acylation.
Step 2: Directing effect of Cl
In chlorobenzene, Cl withdraws electrons inductively but donates a lone pair by resonance. This raises electron density at the ortho and para positions.
Step 3: Result
The acyl group enters ortho and para to Cl, giving 2-chloroacetophenone and 4-chloroacetophenone. The para product is major because the ortho position is crowded.
Final Answer:
Both 2-chloro and 4-chloroacetophenone are formed, which is option (D).
\[ \boxed{\text{(D) }\text{2-Chloroacetophenone and 4-Chloroacetophenone}} \]