Question:
\( \text{CH}_3\text{C} \equiv \text{C}\text{CH}_3 \xrightarrow{\text{H}_2/\text{Pt}} A \xrightarrow{\text{D}_2/\text{Pt}} B \)
The compounds \( A \) and \( B \), respectively, are:
\( \text{CH}_3\text{C} \equiv \text{C}\text{CH}_3 \xrightarrow{\text{H}_2/\text{Pt}} A \xrightarrow{\text{D}_2/\text{Pt}} B \)
The compounds \( A \) and \( B \), respectively, are:
The compounds \( A \) and \( B \), respectively, are:
Show Hint
Syn addition to cis-alkene leads to meso products.
Updated On: Mar 23, 2026
- cis-butene-2 and rac-2,3-dideuterobutane
- trans-butene-2 and rac-2,3-dideuterobutane
- cis-butene-2 and meso-2,3-dideuterobutane
- trans-butene-2 and meso-2,3-dideuterobutane
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Partial hydrogenation of alkyne with Pt gives cis-alkene.
Step 2: Addition of D₂ across double bond occurs syn, forming meso compound.
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