Question

Calculate the solubility of gas in solvent at 25$^{\circ}$C and 0.8 atm if Henry's law constant for solvent is $6.8 \times 10^{-4}$ moldm$^{-3}$ atm$^{-1}$.

• A. $5.88 \times 10^{-4}$ M
• B. $6.12 \times 10^{-4}$ M
• C. $5.44 \times 10^{-4}$ M
• D. $6.48 \times 10^{-4}$ M

Hint:

Solubility is directly proportional to the partial pressure of the gas over the solution.

Answer 1

The Correct Option is C

Step 1: Formula
Henry's Law: $S = K_H \times P$

Step 2: Calculation
Given $K_H = 6.8 \times 10^{-4}$ moldm$^{-3}$ atm$^{-1}$ and $P = 0.8$ atm.
$S = (6.8 \times 10^{-4}) \times 0.8$
$S = 5.44 \times 10^{-4}$ mol/dm$^3$ (or M).

Step 3: Conclusion
The solubility is $5.44 \times 10^{-4}$ M.
Final Answer: (C)