Question:
Calculate the radius of an atom of an element in pm if it forms bcc unit cell structure having edge length $4.3\times10^{-8}$ cm.
Calculate the radius of an atom of an element in pm if it forms bcc unit cell structure having edge length $4.3\times10^{-8}$ cm.
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BCC: $4r = \sqrt{3}a$; FCC: $4r = \sqrt{2}a$.
Updated On: Jun 19, 2026
- 186.2
- 215.0
- 152.3
- 282.8
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The Correct Option is A
Solution and Explanation
Step 1: Formula
For BCC: $r = \frac{\sqrt{3}}{4} a$
Step 2: Analysis
- $a = 4.3 \times 10^{-8}$ cm = 430 pm. - $r = \frac{1.732}{4} \times 430$ - $r = 0.433 \times 430 = 186.19$ pm
Step 3: Conclusion
The radius is approximately 186.2 pm. Final Answer: (A)
For BCC: $r = \frac{\sqrt{3}}{4} a$
Step 2: Analysis
- $a = 4.3 \times 10^{-8}$ cm = 430 pm. - $r = \frac{1.732}{4} \times 430$ - $r = 0.433 \times 430 = 186.19$ pm
Step 3: Conclusion
The radius is approximately 186.2 pm. Final Answer: (A)
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