Question

Calculate the osmotic pressure of a solution containing \(3.42\text{ g}\) of fructose (molar mass = \(180\text{ g/mol}\)) in 1 litre of water at \(400\text{ K}\).

• A. \(0.624\text{ atm}\)
• B. \(0.180\text{ atm}\)
• C. \(0.340\text{ atm}\)
• D. \(0.420\text{ atm}\)

Hint:

Find the molarity from mass and molar mass and use the osmotic pressure equation.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
The osmotic pressure is \(\pi = CRT\).

Step 2: Concentration
\(n = \dfrac{3.42}{180} = 0.019\text{ mol}\) in 1 L, so \(C = 0.019\text{ mol L}^{-1}\).

Step 3: Substitute
\(\pi = 0.019 \times 0.0821 \times 400\)

Step 4: Result
\(\pi = 0.624\text{ atm}\)

Final Answer:
The osmotic pressure is 0.624 atm. \[ \boxed{\text{(A) }0.624\text{ atm}} \]