Calculate the entropy change of surrounding if 2 moles of \( \text{H}_2 \) and 1 mole of \( \text{O}_2 \) gas combine to form 2 moles of liquid water by releasing 525 kJ heat to surrounding at constant pressure and at 300 K.
Show Hint
Surroundings gain entropy when the system releases heat (exothermic).
Step 1: Concept Entropy change of the surroundings (\(\Delta S_{surr}\)) is the heat absorbed by the surroundings divided by the temperature.
Step 2: Meaning Since heat is released by the system, it is absorbed by the surroundings (\(Q_{surr} = -Q_{sys}\)).
Step 3: Analysis \(\Delta S_{surr} = \frac{Q_{surr}}{T} = \frac{525 \text{ kJ}}{300 \text{ K}} = \frac{525000 \text{ J}}{300 \text{ K}}\).
Step 4: Conclusion \(\Delta S_{surr} = 1750 \text{ J K}^{-1}\).
Final Answer: (B)