Question

Calculate the energy stored in a \(10\,\mu F\) capacitor charged to \(50\,V\).

• A. \(0.025\,J\)
• B. \(0.0125\,J\)
• C. \(0.05\,J\)
• D. \(0.1\,J\)

Hint:

Energy stored in a capacitor: \[ U=\frac{1}{2}CV^2 \] Always convert microfarads (\(\mu F\)) to farads before calculation.

Answer 1

The Correct Option is B

Concept: The energy stored in a capacitor is given by \[ U=\frac{1}{2}CV^2 \] where
• \(C\) = capacitance
• \(V\) = potential difference

Step 1: Convert capacitance into SI unit. \[ C=10\,\mu F = 10\times10^{-6}F \] \[ C=1\times10^{-5}F \]

Step 2: Substitute into the formula. \[ U=\frac{1}{2}(1\times10^{-5})(50)^2 \]

Step 3: Simplify the expression. \[ 50^2=2500 \] \[ U=\frac{1}{2}\times10^{-5}\times2500 \] \[ U=0.0125\,J \] \[ \boxed{0.0125\,J} \]