Question:
Calculate the electronegativity of chlorine from bond energy of Cl-F bond (61 kcal mol\(^{-1}\)), F-F (38 kcal mol\(^{-1}\)) and Cl-Cl bond (58 kcal mol\(^{-1}\)) and electronegativity of fluorine 4.0 eV
Calculate the electronegativity of chlorine from bond energy of Cl-F bond (61 kcal mol\(^{-1}\)), F-F (38 kcal mol\(^{-1}\)) and Cl-Cl bond (58 kcal mol\(^{-1}\)) and electronegativity of fluorine 4.0 eV
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Pauling scale: \(\chi_F = 4.0\), \(\chi_{Cl} = 3.16\) (standard), close to 3.22.
Updated On: Apr 23, 2026
- 1.42 eV
- 1.89 eV
- 2.67 eV
- 3.22 eV
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Pauling's electronegativity difference: \(\chi_F - \chi_{Cl} = 0.208 \sqrt{\Delta}\), where \(\Delta = BE_{Cl-F} - \sqrt{BE_{Cl-Cl} \times BE_{F-F}}\).
Step 2: Detailed Explanation:
\(\Delta = 61 - \sqrt{58 \times 38} = 61 - \sqrt{2204} = 61 - 46.95 = 14.05\) kcal mol\(^{-1}\).
\(\chi_F - \chi_{Cl} = 0.208 \times \sqrt{14.05} = 0.208 \times 3.75 = 0.78\).
\(\chi_{Cl} = 4.0 - 0.78 = 3.22\) eV.
Step 3: Final Answer:
Thus, electronegativity of chlorine = 3.22 eV.
Pauling's electronegativity difference: \(\chi_F - \chi_{Cl} = 0.208 \sqrt{\Delta}\), where \(\Delta = BE_{Cl-F} - \sqrt{BE_{Cl-Cl} \times BE_{F-F}}\).
Step 2: Detailed Explanation:
\(\Delta = 61 - \sqrt{58 \times 38} = 61 - \sqrt{2204} = 61 - 46.95 = 14.05\) kcal mol\(^{-1}\).
\(\chi_F - \chi_{Cl} = 0.208 \times \sqrt{14.05} = 0.208 \times 3.75 = 0.78\).
\(\chi_{Cl} = 4.0 - 0.78 = 3.22\) eV.
Step 3: Final Answer:
Thus, electronegativity of chlorine = 3.22 eV.
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