Step 1: Understanding the Concept
For compression at constant external pressure, \(w = -P_{ext}\,\Delta V\).
Work done on the gas is positive.
Step 2: Find the Volume Change
\(\Delta V = 20 - 30 = -10\ \text{dm}^3 = -10\ \text{L}\)
Step 3: Convert the Work
\(w = 4053\ \text{J}\) and \(1\ \text{L atm} = 101.3\ \text{J}\).
So \(w = \dfrac{4053}{101.3} = 40\ \text{L atm}\).
Step 4: Calculation
\(40 = -P(-10)\), so \(P = \dfrac{40}{10} = 4\ \text{atm}\).
Final Answer:
The required external pressure is 4 atm.
\[ \boxed{\text{(A) }4\ \text{atm}} \]