Question:
Calculate the change in internal energy of the system if 20 kJ work is done on the system and it releases 10 kJ heat in a particular reaction.
Calculate the change in internal energy of the system if 20 kJ work is done on the system and it releases 10 kJ heat in a particular reaction.
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Work ON (+) | Work BY (-)
Heat IN (+) | Heat OUT (-)
Heat IN (+) | Heat OUT (-)
Updated On: Apr 26, 2026
- 20 kJ
- 40 kJ
- 10 kJ
- 30 kJ
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The Correct Option is C
Solution and Explanation
Step 1: First Law of Thermodynamics
$\Delta U = Q + W$
Step 2: Sign Convention
- Work done **on** the system ($W$) = $+20 \text{ kJ}$. - Heat **released** by the system ($Q$) = $-10 \text{ kJ}$.
Step 3: Calculation
$\Delta U = (-10 \text{ kJ}) + (+20 \text{ kJ})$
$\Delta U = +10 \text{ kJ}$
Final Answer: (C)
$\Delta U = Q + W$
Step 2: Sign Convention
- Work done **on** the system ($W$) = $+20 \text{ kJ}$. - Heat **released** by the system ($Q$) = $-10 \text{ kJ}$.
Step 3: Calculation
$\Delta U = (-10 \text{ kJ}) + (+20 \text{ kJ})$
$\Delta U = +10 \text{ kJ}$
Final Answer: (C)
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