Question:
Calculate the change in internal energy of the system if \(20\text{ kJ}\) of work is done on the system and it releases \(10\text{ kJ}\) of heat in a particular reaction.
Calculate the change in internal energy of the system if \(20\text{ kJ}\) of work is done on the system and it releases \(10\text{ kJ}\) of heat in a particular reaction.
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Use sign convention carefully: work on system is positive.
Updated On: Apr 26, 2026
- \(30\text{ kJ}\)
- \(10\text{ kJ}\)
- \(-15\text{ kJ}\)
- \(-20\text{ kJ}\)
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The Correct Option is B
Solution and Explanation
Concept:
\[ \Delta U = q + w \] Step 1: Identify signs.
Step 2: Substitute. \[ \Delta U = -10 + 20 = 10 \]
Step 3: Conclusion. \[ \Delta U = 10\text{ kJ} \]
\[ \Delta U = q + w \] Step 1: Identify signs.
- Heat released â \(q = -10\text{ kJ}\)
- Work done on system â \(w = +20\text{ kJ}\)
Step 2: Substitute. \[ \Delta U = -10 + 20 = 10 \]
Step 3: Conclusion. \[ \Delta U = 10\text{ kJ} \]
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