Question:
Calculate \(\Delta \text{T}_b\) of \(0.02 \text{ m}\) solution if molal elevation constant for solvent is \(0.52 \text{ K kg mol}^{-1}\).
Calculate \(\Delta \text{T}_b\) of \(0.02 \text{ m}\) solution if molal elevation constant for solvent is \(0.52 \text{ K kg mol}^{-1}\).
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Formula: \(\Delta T_b = K_b m\) (for non-electrolytes, \(i=1\)).
Updated On: May 4, 2026
- 0.0104 K
- 0.0202 K
- 0.0304 K
- 0.0416 K
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The Correct Option is A
Solution and Explanation
Concept:
\[ \Delta T_b = K_b \times m \]
Step 1: Substitute values \[ \Delta T_b = 0.52 \times 0.02 \]
Step 2: Calculate \[ \Delta T_b = 0.0104 \text{ K} \] Conclusion: \[ \text{Elevation in boiling point = 0.0104 K} \]
\[ \Delta T_b = K_b \times m \]
Step 1: Substitute values \[ \Delta T_b = 0.52 \times 0.02 \]
Step 2: Calculate \[ \Delta T_b = 0.0104 \text{ K} \] Conclusion: \[ \text{Elevation in boiling point = 0.0104 K} \]
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