>
Exams
>
Chemistry
>
Nuclear physics
>
cadmium is used in nuclear reactors for
Question:
Cadmium is used in nuclear reactors for?
Show Hint
Control rods absorb excess neutrons to control fission rate.
BITSAT - 2017
BITSAT
Updated On:
Mar 20, 2026
absorbing neutrons
cooling
release neutrons
increase energy
Show Solution
Verified By Collegedunia
The Correct Option is
A
Solution and Explanation
Cadmium has a very high neutron absorption cross-section and is used in control rods to regulate nuclear reactions.
Download Solution in PDF
Was this answer helpful?
0
0
Top BITSAT Chemistry Questions
How many moles of oxygen are required to completely combust 1 mole of propane (C\(_3\)H\(_8\))?
BITSAT - 2026
Chemistry
Hydrocarbons
View Solution
Which of the following substances does not undergo hydrolysis in aqueous solution?
BITSAT - 2026
Chemistry
Hydrolysis of salts
View Solution
A first-order reaction is 25% complete in 30 minutes. How much time will it take for the reaction to be 75% complete?
BITSAT - 2026
Chemistry
Collision Theory of Chemical Reactions
View Solution
What is the IUPAC name of the compound: CH\(_3\) – CH\(_2\) – CH(CH\(_3\)) – CH\(_2\) – CH\(_3\)
BITSAT - 2026
Chemistry
introduction to organic chemistry
View Solution
Which of the following gases has the highest rate of diffusion?
BITSAT - 2026
Chemistry
Gas laws
View Solution
View More Questions
Top BITSAT Nuclear physics Questions
Cadmium is used in nuclear reactors for?
BITSAT - 2021
Chemistry
Nuclear physics
View Solution
$1 \,g$
of
$U -235$
is converted into
$UF _{6}$
. The radioactivity of
$UF _{6}$
thus obtained is :
BITSAT - 2011
Chemistry
Nuclear physics
View Solution
Top BITSAT Questions
Two lighter nuclei combine to form a comparatively heavier nucleus by the relation \[ \frac{2}{1}\text{X} + \frac{2}{1}\text{X} = \frac{4}{2}\text{Y} \] The binding energies per nucleon of \( \frac{2}{1}\text{X} \) and \( \frac{4}{2}\text{Y} \) are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is
BITSAT - 2026
Nuclei
View Solution
The equation of a plane passing through three non-collinear points is determined using:
BITSAT - 2026
Plane
View Solution
Let \( A = \begin{bmatrix} 1 & 0 & 0 0 & 1 & 0 3 & 2 & 1 \end{bmatrix} \). Find \( A^{100} \).
BITSAT - 2026
types of matrices
View Solution
Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L: \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines PN and PQ, then \( \cos \alpha \) is equal to
BITSAT - 2026
Three Dimensional Geometry
View Solution
The magnitude of projection of line joining (3, 4, 5) and (4, 6, 3) on the line joining (−1, 2, 4) and (1, 0, 5) is
BITSAT - 2026
Three Dimensional Geometry
View Solution
View More Questions