Question:
By increasing the temperature, the specific resistance of a conductor and a semiconductor respectively
By increasing the temperature, the specific resistance of a conductor and a semiconductor respectively
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Conductivity is the reciprocal of resistivity; it behaves exactly the opposite.
Updated On: Apr 30, 2026
- increases, increases.
- decreases, decreases.
- increases, decreases.
- decreases, increases.
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The Correct Option is C
Solution and Explanation
Step 1: Conductors
For conductors, relaxation time ($\tau$) decreases as temperature increases due to more collisions. Since $\rho \propto 1/\tau$, specific resistance increases.
Step 2: Semiconductors
For semiconductors, the increase in charge carrier density ($n$) outweighs the decrease in relaxation time. Since $\rho \propto 1/n$, specific resistance decreases.
Step 3: Comparison
Conductor: Positive temperature coefficient. Semiconductor: Negative temperature coefficient.
Step 4: Conclusion
Conductor resistance increases; semiconductor resistance decreases.
Final Answer:(C)
For conductors, relaxation time ($\tau$) decreases as temperature increases due to more collisions. Since $\rho \propto 1/\tau$, specific resistance increases.
Step 2: Semiconductors
For semiconductors, the increase in charge carrier density ($n$) outweighs the decrease in relaxation time. Since $\rho \propto 1/n$, specific resistance decreases.
Step 3: Comparison
Conductor: Positive temperature coefficient. Semiconductor: Negative temperature coefficient.
Step 4: Conclusion
Conductor resistance increases; semiconductor resistance decreases.
Final Answer:(C)
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