Step 1: Understanding the Concept
Red P and \(\text{Br}_{2}\) form \(\text{PBr}_{3}\), which replaces the OH group of an alcohol with Br.
Step 2: Product
\(\text{CH}_{3}\text{CH(OH)CH}_{2}\text{CH}_{3}\rightarrow\text{CH}_{3}\text{CHBrCH}_{2}\text{CH}_{3}\) (2-bromobutane).
Step 3: Count isomers
C-2 carries four different groups: H, Br, \(\text{CH}_{3}\) and \(\text{C}_{2}\text{H}_{5}\). It is the only chiral centre, so the number of optical isomers is \(2^{n}=2^{1}=2\).
Final Answer:
The product has two optical isomers.
\[ \boxed{\text{(C) }\text{Two}} \]