Question:
Borazole is prepared by heating the product isolated by reacting
Borazole is prepared by heating the product isolated by reacting
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Borazole ($\text{B}_3\text{N}_3\text{H}_6$) is structural and isoelectronic with benzene ($\text{C}_6\text{H}_6$). It is synthesized by the reaction of diborane ($\text{B}_2\text{H}_6$) with ammonia ($\text{NH}_3$). Another common laboratory synthesis involves reacting $\text{BCl}_3$ with $\text{NH}_4\text{Cl}$.
Updated On: May 28, 2026
- boron with dinitrogen.
- diborane with ammonium nitrate.
- diborane with ammonia.
- boron with ammonia.
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Question:
The question asks for the reactants required to prepare borazole (also known as inorganic benzene, $\text{B}_3\text{N}_3\text{H}_6$).
Step 2: Detailed Explanation:
Borazole ($\text{B}_3\text{N}_3\text{H}_6$) can be prepared by reacting diborane ($\text{B}_2\text{H}_6$) with ammonia ($\text{NH}_3$) in a $1:2$ molar ratio at low temperatures to form an addition product (diammoniate of diborane), which on heating to higher temperatures (about $200^\circ\text{C}$) decomposes to give borazole:
\[ 3\text{B}_2\text{H}_6 + 6\text{NH}_3 \rightarrow 3[\text{BH}_2(\text{NH}_3)_2]^+[\text{BH}_4]^- \xrightarrow{\Delta, 200^\circ\text{C}} 2\text{B}_3\text{N}_3\text{H}_6 + 12\text{H}_2 \]
Alternatively, heating a mixture of diborane and ammonia directly at higher temperatures yields borazole.
Therefore, the reactant pair is diborane with ammonia.
Step 3: Final Answer:
The correct option is (C).
The question asks for the reactants required to prepare borazole (also known as inorganic benzene, $\text{B}_3\text{N}_3\text{H}_6$).
Step 2: Detailed Explanation:
Borazole ($\text{B}_3\text{N}_3\text{H}_6$) can be prepared by reacting diborane ($\text{B}_2\text{H}_6$) with ammonia ($\text{NH}_3$) in a $1:2$ molar ratio at low temperatures to form an addition product (diammoniate of diborane), which on heating to higher temperatures (about $200^\circ\text{C}$) decomposes to give borazole:
\[ 3\text{B}_2\text{H}_6 + 6\text{NH}_3 \rightarrow 3[\text{BH}_2(\text{NH}_3)_2]^+[\text{BH}_4]^- \xrightarrow{\Delta, 200^\circ\text{C}} 2\text{B}_3\text{N}_3\text{H}_6 + 12\text{H}_2 \]
Alternatively, heating a mixture of diborane and ammonia directly at higher temperatures yields borazole.
Therefore, the reactant pair is diborane with ammonia.
Step 3: Final Answer:
The correct option is (C).
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