Question:
Bond dissociation energy is $F_2 > Cl_2$.
$Cl_2$ has more electronic repulsion than $F_2$.
Bond dissociation energy is $F_2 > Cl_2$.
$Cl_2$ has more electronic repulsion than $F_2$.
Updated On: Jul 28, 2022
- If both assertion and reason are true and reason is the correct explanation of assertion.
- If both assertion and reason are true but reason is not the correct explanation of assertion.
- If assertion is true but reason is false.
- If both assertion and reason are false.
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The Correct Option is D
Solution and Explanation
Bond dissociation energy is $F _{2}< Cl _{2}$ because of relatively large electron-electron repulsion among the lone pairs in $F _{2}$ molecule where they are much closer to each other than in $Cl _{2}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family